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5k^2+50k+80=0
a = 5; b = 50; c = +80;
Δ = b2-4ac
Δ = 502-4·5·80
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-30}{2*5}=\frac{-80}{10} =-8 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+30}{2*5}=\frac{-20}{10} =-2 $
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